94 lines
3.4 KiB
SQL
94 lines
3.4 KiB
SQL
select * from iiabmdb.with_exp_result limit 0, 20;
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select count(distinct s_id) from iiabmdb.with_exp_result;
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select count(*) from iiabmdb.with_exp_sample;
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select distinct s_id, id_firm, id_product from iiabmdb.with_exp_result order by s_id, id_firm, id_product;
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select distinct s_id, count(distinct id_firm, id_product) as count_firm_prod from iiabmdb.with_exp_result group by s_id;
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select distinct s_id, count(distinct id_firm, id_product) as count_firm_prod
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from iiabmdb.with_exp_result group by s_id;
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select distinct s_id,
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count(distinct id_firm, id_product) as count_firm_prod,
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count(distinct id_firm) as count_firm,
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count(distinct id_product) as count_prod
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from iiabmdb.with_exp_result group by s_id;
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# 控制问题需要处理，否则最后 experiment avg出来的东西不对
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# 1 2 3
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select
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idx_scenario,
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sum(count_firm_prod) / count(*) as mean_count_firm_prod, # Note to use count(*), to include NULL
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sum(count_firm) / count(*) as mean_count_firm,
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sum(count_prod) / count(*) as mean_count_prod
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from (
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select sample.id, idx_scenario, count_firm_prod, count_firm, count_prod
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from iiabmdb.with_exp_sample as sample
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left join iiabmdb.with_exp_experiment as experiment
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on sample.e_id = experiment.id
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left join (select s_id,
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count(distinct id_firm, id_product) as count_firm_prod,
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count(distinct id_firm) as count_firm,
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count(distinct id_product) as count_prod
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from iiabmdb.with_exp_result group by s_id) as s_count
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on sample.id = s_count.s_id) as secnario_count
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group by idx_scenario;
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# 4 5 6
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select sample.id, idx_scenario, max_ts_firm_prod, max_ts_firm, max_ts_prod
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from iiabmdb.with_exp_sample as sample
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left join iiabmdb.with_exp_experiment as experiment
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on sample.e_id = experiment.id
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left join # firm prod
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(select s_id, max(ts) as max_ts_firm_prod from
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(select s_id, id_firm, id_product, min(ts) as ts
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from iiabmdb.with_exp_result
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where `status` = "D"
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group by s_id, id_firm, id_product) as ts
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group by s_id) as s_max_ts_firm_prod
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on sample.id = s_max_ts_firm_prod.s_id
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left join # firm
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(select s_id, max(ts) as max_ts_firm from
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(select s_id, id_firm, min(ts) as ts
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from iiabmdb.with_exp_result
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where `status` = "D"
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group by s_id, id_firm) as ts
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group by s_id) as s_max_ts_firm
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on sample.id = s_max_ts_firm.s_id
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left join # prod
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(select s_id, max(ts) as max_ts_prod from
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(select s_id, id_product, min(ts) as ts
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from iiabmdb.with_exp_result
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where `status` = "D"
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group by s_id, id_product) as ts
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group by s_id) as s_max_ts_prod
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on sample.id = s_max_ts_prod.s_id;
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# 7 8 9
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select sample.id, idx_scenario, n_remove_firm_prod, n_all_prod_remove_firm, end_ts
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from iiabmdb.with_exp_sample as sample
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left join iiabmdb.with_exp_experiment as experiment
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on sample.e_id = experiment.id
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left join
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(select s_id, count(distinct id_firm, id_product) as n_remove_firm_prod
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from iiabmdb.with_exp_result
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where `status` = "R"
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group by s_id) as s_n_remove_firm_prod
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on sample.id = s_n_remove_firm_prod.s_id
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left join
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(select s_id, count(distinct id_firm) as n_all_prod_remove_firm from
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(select s_id, id_firm, count(distinct id_product) as n_remove_prod
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from iiabmdb.with_exp_result
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where `status` = "R"
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group by s_id, id_firm) as s_n_remove_prod
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left join iiabmdb_basic_info.firm_n_prod as firm_n_prod
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on s_n_remove_prod.id_firm = firm_n_prod.code
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where n_remove_prod = n_prod
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group by s_id) as s_n_all_prod_remove_firm
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on sample.id = s_n_all_prod_remove_firm.s_id
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left join
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(select s_id, max(ts) as end_ts
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from iiabmdb.with_exp_result
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group by s_id) as s_end_ts
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on sample.id = s_end_ts.s_id; |